Borek said:
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I am not sure what you mean by Cu/graphite - solid Cu and graphite, or Cu2+ and graphite? For the cell (galvanic) to work you need two half reactions. One must be reduction, the other one oxidation. Having just a solution of cation may give you system ready for reduction, but what is going to be oxidized? Try to write reaction equations.
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Sorry, I was not clear...
What I really wanted to find out is :
In chemical Cells - if the electrodes are Copper (solid) and Graphite (instead of the usual cells with two different metals) in a electrolyte of aq NaOH, will it works?
What about if it is Magnesium(solid) and Graphite instead - in the same settings.
I was wondering - the cells work on redox. In Cu / Mg electrodes cell, the more reactive metal Mg oxidizes and gives off electrons and becomes the negative terminal, the electrons than travels to Cu electrode and forms a close circuit with the aq NaOH. and the cell is functioning.
In Copper / Graphite [and Magnesium / Graphite] case mentioned, Graphite is not part of the metal reactivity series. And hence with the Graphite oxidizes and gives off electrons ? It most likely not - as what ions will Graphite form? Then, will the set up actually works?
Would it work for Magnesium / Graphite electrode case? Mg is more reactive, hence oxidises and becomes negative electrode, the electrons then travels to the Graphite electrode into the aq NaOH to form a close circuit... would this be correct way of reasoning?
Very interesting - juz that I do not have a lab to just try it out and confirm if the set up can work or not ?
Anyone can help?
Many thanks...
Sorry, I was not clear...What I really wanted to find out is :In chemical Cells - if the electrodes are Copper (solid) and Graphite (instead of the usual cells with two different metals) in a electrolyte of aq NaOH, will it works?What about if it is Magnesium(solid) and Graphite instead - in the same settings.I was wondering - the cells work on redox. In Cu / Mg electrodes cell, the more reactive metal Mg oxidizes and gives off electrons and becomes the negative terminal, the electrons than travels to Cu electrode and forms a close circuit with the aq NaOH. and the cell is functioning.In Copper / Graphite [and Magnesium / Graphite] case mentioned, Graphite is not part of the metal reactivity series. And hence with the Graphite oxidizes and gives off electrons ? It most likely not - as what ions will Graphite form? Then, will the set up actually works?Would it work for Magnesium / Graphite electrode case? Mg is more reactive, hence oxidises and becomes negative electrode, the electrons then travels to the Graphite electrode into the aq NaOH to form a close circuit... would this be correct way of reasoning?Very interesting - juz that I do not have a lab to just try it out and confirm if the set up can work or not ?Anyone can help?Many thanks...
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